5110 views|4 replies

2493

Posts

0

Resources
The OP

Matlab Lesson 6 - Graphics Beautification and Blocking! [Copy link]

This is mainly about some settings!!! [ This post was last edited by gaoxiao on 2009-6-14 20:05 ]
This post is from Microcontroller MCU
Personal signature我的邮箱gaoxiaoan123@163.com!回帖是一种美德!互相帮助,共同进步!
口头禅:生活在于创造机会,把握机会!

2493

Posts

0

Resources
2
t=0:pi/20:2*pi [x,y]=meshgrid(t) subplot(2,2,1) plot(sin(t),cos(t)) axis equal subplot(2,2,2 ) z=sin(x)+cos(y) plot(t,z) axis([0 2*pi -2 2]) subplot(2,2,3) z=sin(x).*cos(y) plot(t,z) axis([0 2*pi -1 1]) subplot(2,2,4) z=(sin(x).^2)- (cos(y).^2) plot(t,z) axis([0 2*pi -1 1])
This post is from Microcontroller MCU
Personal signature我的邮箱gaoxiaoan123@163.com!回帖是一种美德!互相帮助,共同进步!
口头禅:生活在于创造机会,把握机会!

2493

Posts

0

Resources
3
This post is from Microcontroller MCU
Personal signature我的邮箱gaoxiaoan123@163.com!回帖是一种美德!互相帮助,共同进步!
口头禅:生活在于创造机会,把握机会!

2493

Posts

0

Resources
4
If you have any questions, please remember to contact me, or leave me a message! The notes for this lesson will be incomplete in the future. There are some edits designed, which is a bit troublesome!
This post is from Microcontroller MCU
Personal signature我的邮箱gaoxiaoan123@163.com!回帖是一种美德!互相帮助,共同进步!
口头禅:生活在于创造机会,把握机会!

2493

Posts

0

Resources
5
t=0:pi/20:2*pi %pi is the ratio of a circle to a circle [x,y]=meshgrid(t) %Draw subplot(2,2,1) %The following subplots are drawn separately plot(sin(t),cos(t)) axis equal subplot(2,2,2) z=sin(x)+cos(y) plot(t,z) axis([0 2*pi -2 2]) %Set the range of coordinates! subplot(2,2,3) z=sin(x).*cos(y) plot(t,z) axis([0 2*pi -1 1]) subplot(2,2,4) z=sin(x).^2)-(cos(y).^2) plot(t,z) axis([0 2*pi -1 1])
This post is from Microcontroller MCU
Personal signature我的邮箱gaoxiaoan123@163.com!回帖是一种美德!互相帮助,共同进步!
口头禅:生活在于创造机会,把握机会!

Guess Your Favourite
Find a datasheet?

EEWorld Datasheet Technical Support

Related articles more>>
    Copyright © 2005-2025 EEWORLD.com.cn, Inc. All rights reserved 京B2-20211791 京ICP备10001474号-1 电信业务审批[2006]字第258号函 京公网安备 11010802033920号
    快速回复 返回顶部 Return list