1: If the LED is lit by the pull-up resistor method, then when the i/0 is low, the current will flow into the MUC due to bypass. Assuming the resistor is 1K LED2V, (5)/1000 = 5ma. If all 32 I/0 ports
The Future of Code Chapter 1 Time and Space of Programming 1.1 The Essence of Programming 3 The Essence of Programming is Thinking 4 The Joy of Creating the World 4 Rapidly Improving Performance Has C
For a long time, the power supply system has always been an important and important aspect of weak current projects. Because the specifications and requirements of weak current are higher than those o
The memory is managed in segments and pages. When a new process is added, how does the operating system allocate memory to the process? The simplest method is best. Thank you in advance.