The oscillation process of a multivibrator a

It can be seen from the circle that when vri is turned off, \0[2 is turned on, and the current passes through RJ and Ci: When VT1 is turned on,
the charged Cl begins to discharge. Then charge cl in reverse phase, the №I voltage becomes positive, and vri becomes conductive. So uc: approaches 0, causing the base of VT2
to become negative, and VT2 becomes cut off again. In this way, VT1 and VT2 are turned on and off alternately to form an oscillation state.