Please tell me about using DSP28335 timer to control LED flashing

zhuhaow

Please tell me about using DSP28335 timer to control LED flashing [Copy link]

#include"DSP2833x_Project.h" void delay(Uint32 i) { while(i--); } #define LED1_ON GpioDataRegs.GPASET.bit.GPIO0=1; #define LED2_ON GpioDataRegs.GPASET.bit.GPIO1=1; #define LED3_ON GpioDataRegs.GPASET.bit.GPIO2=1; #define LED4_ON GpioDataRegs.GPASET.bit.GPIO3=1; #define LED5_ON GpioDataRegs.GPASET.bit.GPIO4=1; #define LED6_ON GpioDataRegs.GPASET.bit.GPIO5=1; #define LED7_ON GpioDataRegs.GPASET.bit.GPIO24=1; #define LED8_ON GpioDataRegs.GPASET.bit.GPIO25=1; #define LED1_OFF GpioDataRegs.GPACLEAR.bit.GPIO0=0; #define LED2_OFF GpioDataRegs.GPACLEAR.bit.GPIO1= 0; #define LED3_OFF GpioDataRegs.GPACLEAR.bit.GPIO2=0; #define LED4_OFF GpioDataRegs.GPACLEAR.bit.GPIO3=0; #define LED5_OFF GpioDataRegs.GPACLEAR.bit.GPIO4=0; #define LED6_OFF GpioDataRegs.GPACLEAR.bit. GPIO5=0; #define LED7_OFF GpioDataRegs.GPACLEAR.bit.GPIO24=0; #define LED8_OFF GpioDataRegs.GPACLEAR.bit.GPIO25=0; interrupt void timer0_isr(void); void main(void) { InitSysCtrl(); DINT; InitPieCtrl (); IFR=0X0000; IER=0X0000; InitPieVectTable(); EALLOW; PieVectTable.TINT0=&timer0_isr; EDIS; puTimer0Regs .TCR.all=0x4001; IER|=M_INT1; PieCtrlRegs.PIEIER1.bit.INTx7=1; EINT; for(;;); } int shu; interrupt void timer0_isr(void) { shu++; LED1_ON; delay(5000000); LED1_OFF; LED2_ON; delay(5000000); LED2_OFF; LED3_ON; delay(5000000); LED3_OFF; LED4_ON; delay(5000000); LED4_OFF; LED5_ON; delay(5000000); LED5_OFF; LED6_ON; delay(5000000); (5000000); LED7_OFF; LED8_ON; delay(5000000); LED8_OFF; PieCtrlRegs.PIEACK.all=0x01; CpuTimer0Regs.TCR.bit.TRB=0; CpuTimer0Regs.TCR.bit.TIF=1; } The above is the program I wrote . The result of running on the board is that the lights light up once in a cycle and then go out. What's wrong with this program?

elvike

If you use so many delays in your interrupt program, there may be an interrupt conflict. If you light the lamp in this way, there is no need to use interrupts. If you use interrupts, there is no need for delay.

QQ20041050

It is recommended to write flags in interrupts, but not to write programs. You can turn off the interrupt enable after entering the interrupt, and then turn on the interrupt after the program is finished running.

zhuhaow

elvike published on 2017-7-4 20:23 If you use so many delays in your interrupt program, there may be an interrupt conflict. If you light the lights like this, there is no need to use interrupts. Using interrupts eliminates the need...

How to achieve the effect of running lights without delay?

zhuhaow

QQ20041050 Published on 2017-7-4 21:17 It is recommended to write flags in interrupts, but not to write programs. You can turn off the interrupt enable after entering the interrupt, and then turn on the interrupt after the program is finished running.

Yeah, thanks for the reply. I'll give it a try.

zhuhaow

QQ20041050 Published on 2017-7-4 21:17 It is recommended to write flags in interrupts, but not to write programs. You can turn off the interrupt enable after entering the interrupt, and then turn on the interrupt after the program is finished running.

Turning TIE off and on again as you said still doesn't work. . It won't light up as long as it is turned off.

zhuhaow

elvike published on 2017-7-4 20:23 If you use so many delays in your interrupt program, there may be an interrupt conflict. If you light the lamp like this, there is no need to use interrupts. If you use interrupts, there is no need...

It seems that the delay still doesn't work. I don't know what the problem is. The interrupt keeps running.

elvike

Use the emulator to add a breakpoint in the interrupt to see if the interrupt is entered. If it is, use an oscilloscope to check the status of your IO port. Your thinking is not very clear, or you do not know how the interrupt is related to the main program. relation.

zhuhaow

elvike published on 2017-7-23 15:08 Use the emulator to add a breakpoint in the interrupt to see if the interrupt is entered. If it is, use an oscilloscope to check the status of your IO port. Your idea is not very clear...

Thank you. I added a variable to the interrupt. The variable keeps adding itself, which means it enters the interrupt. I am using a DSP28335 board. The LED light does not have an output IO port, but I can use the GPIO bits to define and control the high and low level status of the LED. How do I detect the IO port status?

elvike

zhuhaow published on 2017-7-23 15:38 Thank you. I added a variable to the interrupt. The variable keeps adding itself, which means it enters the interrupt. I am using a DSP28335 board, but the LED lights are not...

Use an oscilloscope and a multimeter. Take a look at ti's routines. There are examples of GPIO toggle in there.