Inverter circuit principle for lighting 6~8W fluorescent lamps

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The picture shows the principle of the inverter circuit for lighting 6~8W fluorescent lamps . This circuit is suitable for lighting 6 to 8 W fluorescent tubes. All parameters of the circuit are marked in the figure. When using a 6 W ordinary fluorescent lamp , the supply voltage is 6~12 V, the current is 0.3~0.6 A, and the voltage at both ends of the lamp is about 45~65V when it is not started.